Show the homolysis reaction of benzoyl peroxide,$(C_6H_5CO)_2O_2$.
The homolysis of benzoyl peroxide $(C_6H_5CO)_2O_2$ involves the cleavage of the $O-O$ bond to form two benzoyloxy radicals,which subsequently undergo decarboxylation to form phenyl radicals and carbon dioxide:
$(C_6H_5CO)_2O_2$ $\xrightarrow{\text{Homolysis}} 2 C_6H_5COO\bullet$ $\rightarrow 2 C_6H_5\bullet + 2 CO_2$
$(C_6H_5CO)_2O_2$ $\xrightarrow{\text{Homolysis}} 2 C_6H_5COO\bullet$ $\rightarrow 2 C_6H_5\bullet + 2 CO_2$
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What is the shape of the methyl carbocation,$\overset{\oplus}{C}H_3$?
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Among the given compounds $I, II, III$,the correct order of bond dissociation energy of the $C-H$ bond marked with $*$ is:
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View SolutionConsider the following carbocations. What is the relative stability order of these carbocations?
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$(3)$ $CH_3-C_6H_4-CH_2^+$
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